You can use the CommonDialog to get the Lang File
which you want to edit. Or can use (menu) Open_ File_New command
and input the complete File with path.
Use Open_ File_New if the CommandDialog starts displaying odd behaviour with a particular File.
EDITING OPTIONS : -
Use RECORD_DELETE to delete all data of a particular word.(A blank entry can be observed in views )
Use RECORD_RENAME to rename the particular word. You may better change the word in its box and resave it.
You may RECORD_ADD a new word and its data working offline. Fill up the WORD and all its 'String Compare Protocols'. Rate every entry carefully.
For every word you will be provided some data like no. of divisons (i.e. no of divisons the word would get divided ) and the average time length. You can bring that from memory from the menu "Current Memory" and "Display Current Memory". Note the average and if necessary, edit its average time length entry. Press Add and then 'Resave' or 'Add' for a existing word or a new word respectively.
We repeat ...
When you enter a new protocol or the
complete GOLDEN string from memory then press 'Add'. to put it
inside the list.
After this you will HAVE to save it
to disk...
So Press " Resave" if you
are saving for the same word or use menu "Record_Add"
if you are saving for a new word.
Edit a protocol and its rating you had previously entered by pressing 'Edit'. Just follow instructions.
You may also move through the records using NEXT or PREVIOUS menus.
Use (menu) "File _View all titles
of entries." to view all the entered titles.
The "Word Features" displays all the details of the word in your language font.
String compare protocols generate
a LIKE match with a final GOLDEN Chara ( produced by the vocabulary
characters .)
As an example, for "Introduction"
you may have a basic vocabulary response like eeooucssan, use
this string production to input a STRING COMPARE PROTOCOL like
...
*ucssan = 60 % Rated: Introduction
*ssan = 50 % Rated : Introduction.
These protocols give us the final word. Through trials you may find that 90% recognition can be achieved for words.
This is the length of the word you spoke in bytes.
For a recording frequency of 22.5 Khz. :: Introduction
:: will generate a average of 18000 bytes.
In time units this is 18000/22050 = 0.8 secs.
Some words have detectable gaps which are their peculiar
features.
Example eight = Eigh ^ th No. of divisons = 2